1/12x^2-1/3x=16

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Solution for 1/12x^2-1/3x=16 equation: 


x in (-oo:+oo)

(1/12)*x^2-((1/3)*x) = 16 // - 16

(1/12)*x^2-((1/3)*x)-16 = 0

(1/12)*x^2+(-1/3)*x-16 = 0

1/12*x^2-1/3*x-16 = 0

DELTA = (-1/3)^2-(-16*1/12*4)

DELTA = 49/9

DELTA > 0

x = ((49/9)^(1/2)+1/3)/(1/12*2) or x = (1/3-(49/9)^(1/2))/(1/12*2)

x = 16 or x = -12

x in { -12, 16 }

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